In the standing wave $y=2A\sin\omega t\cos kx$, antinodes occur where the amplitude is
AZero
B$A$
CMaximum, equal to $2A$
DMaximum, equal to $\dfrac{A}{2}$
Answer & Solution
Correct answer: C. Maximum, equal to $2A$
The amplitude of the standing wave is $2A|\cos kx|$. At antinodes, $|\cos kx|=1$, so the amplitude becomes maximum and equals $2A$.
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