Consider the list of five numbers $4$, $4$, $6$, $7$, $10$. If the value $10$ is replaced by $24$ (so the new list is $4$, $4$, $6$, $7$, $24$), which of the following statements is correct?

**Mean (changes):** The original mean is $\dfrac{4+4+6+7+10}{5} = \dfrac{31}{5} = 6.2$. The new mean is $\dfrac{4+4+6+7+24}{5} = \dfrac{45}{5} = 9$. The mean has jumped from $6.2$ to $9$. **Median (unchanged):** In both lists the data are already in increasing order and have $n = 5$ (odd). The median is the middle value — the third one. In both lists that value is $\mathbf{6}$. Replacing $10$ with $24$ changes the **largest** value only; it doesn't shift the middle. This is exactly why textbooks present the median as the *robust* measure of center: a single outlier moves the mean significantly but leaves the median fixed.