In the figure above, lines $k$ and $m$ are parallel and are cut by a transversal $p$, forming eight angles. Four of the angles measure $x^{\circ}$ and the remaining four measure $y^{\circ}$. If $x = 110$, what is $y$?

When a transversal cuts two parallel lines, the eight angles produced are split into two congruence classes — one set of four equal acute angles, and one set of four equal obtuse angles. Any acute angle and any obtuse angle in this configuration are **supplementary** (they together form a straight angle on the line). So $x + y = 180$. With $x = 110$, we get $y = 180 - 110 = 70$. - Trap A ($55$) is half of $x$ — would apply only if a line were *bisecting* the angle. - Trap C ($90$) treats the lines as if they met at a right angle. - Trap D ($110$) ignores the figure entirely and matches the two groups, which violates the figure (the angles are split into two distinct measures). Note: without the figure you can't see the eight-angle pattern, so this question is figure-anchored.