alleryStart learning →The prime factorization of $1{,}155$ is:
A$3 \times 5 \times 7 \times 11$
B$3 \times 5 \times 77$
C$5 \times 7 \times 33$
D$3^2 \times 5 \times 7 \times 11$
Answer & Solution
Correct answer: A. $3 \times 5 \times 7 \times 11$
A prime factorization must list **only primes**. Options B and C use composite numbers (77 = 7·11, 33 = 3·11)
so they are products of factors but not prime factorizations.
Divide successively by primes: $1155 / 3 = 385$, $385 / 5 = 77$, $77 / 7 = 11$, and 11 is prime. So $1155 = 3 \times 5 \times 7 \times 11$.
Option D introduces an extra factor of 3, giving $3465 \ne 1155$.
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