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The magnetic field at a perpendicular distance $r$ from a long straight current-carrying wire of current $I$ is given by:
A$B = \dfrac{\mu_0 I r}{2\pi}$
B$B = \dfrac{\mu_0 I}{2\pi r}$
C$B = \mu_0 I r$
D$B = \dfrac{\mu_0 I}{4\pi r^2}$
Answer & Solution
Correct answer: B. $B = \dfrac{\mu_0 I}{2\pi r}$
From Ampère's law applied to a circular loop of radius $r$ centred on the wire:
$\oint \vec{B} \cdot d\vec{l} = \mu_0 I \Rightarrow B (2\pi r) = \mu_0 I \Rightarrow B = \dfrac{\mu_0 I}{2\pi r}$.
Direction: right-hand rule. Curl fingers along the current, thumb points along the magnetic field circulation.
The $1/r$ dependence (not $1/r^2$) is characteristic of a *line* source — same shape as the electric field of an infinite line charge.
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