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The point that divides the line segment joining $A(x_1, y_1, z_1)$ and $B(x_2, y_2, z_2)$ internally in the ratio $m : n$ has coordinates:
A$(m x_1 + n x_2, m y_1 + n y_2, m z_1 + n z_2)$
B$\left(\dfrac{x_1 + x_2}{2}, \dfrac{y_1 + y_2}{2}, \dfrac{z_1 + z_2}{2}\right)$
C$\left(\dfrac{m x_2 + n x_1}{m + n}, \dfrac{m y_2 + n y_1}{m + n}, \dfrac{m z_2 + n z_1}{m + n}\right)$
D$\left(\dfrac{m x_1 + n x_2}{m + n}, \dfrac{m y_1 + n y_2}{m + n}, \dfrac{m z_1 + n z_2}{m + n}\right)$
Answer & Solution
Correct answer: C. $\left(\dfrac{m x_2 + n x_1}{m + n}, \dfrac{m y_2 + n y_1}{m + n}, \dfrac{m z_2 + n z_1}{m + n}\right)$
Internal section formula: when point $P$ divides $\overline{AB}$ such that $AP : PB = m : n$, then
$P = \left(\dfrac{m x_2 + n x_1}{m + n}, \dfrac{m y_2 + n y_1}{m + n}, \dfrac{m z_2 + n z_1}{m + n}\right)$.
The weight $m$ multiplies the *far* endpoint ($B$) and $n$ multiplies the near endpoint ($A$). Easy to flip the assignment if you don't think about which side the ratio means.
When $m = n$, this collapses to the midpoint formula (option C).
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