The gravitational potential energy of a body of mass $m$ raised to a height $h$ above the ground (where $g$ is acceleration due to gravity) is:
A$\dfrac{1}{2} m g h$
B$m g h$
C$m g h^2$
D$m^2 g h$
Answer & Solution
Correct answer: B. $m g h$
Near Earth's surface (where $g$ is approximately constant), gravitational potential energy stored when an object of mass $m$ is lifted by height $h$ equals the work done against gravity: $W = F \cdot s = (mg)(h) = mgh$.
The reference (zero) for PE is conventional, usually the ground. Lower than ground gives negative PE.
Option A ($\tfrac{1}{2} mgh$) is a common trap — students confuse the $\tfrac{1}{2}$ factor that comes from spring or kinetic energy with gravitational PE.
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