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A function $f:A\to B$ is onto (surjective) if:
Aevery element of $B$ has a pre-image in $A$
B$A$ and $B$ are equal
Cdistinct inputs give distinct outputs
Dit has an inverse always
Answer & Solution
Correct answer: A. every element of $B$ has a pre-image in $A$
Surjective (onto): every codomain element is the image of some domain element (range = codomain).
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