Home › JEE Main › mathematics › Complex Numbers and Quadratic Equations › The complex conjugate of $3 - 4i$ is:
The complex conjugate of $3 - 4i$ is:
A$-3 - 4i$
B$4 - 3i$
C$3 + 4i$
D$-3 + 4i$
Answer & Solution
Correct answer: C. $3 + 4i$
The conjugate of a + ib is a − ib, so conj(3 − 4i) = 3 + 4i.
Related questions
The number of distinct $n$th roots of a non-zero complex number is:Using De Moivre's theorem, $(\cos\theta + i in\theta)^4$ equals:The modulus of $z = 5 + 12i$ is:The conjugate of $z = 3 - 4i$ is:If $z = a + ib$ is non-zero, its multiplicative inverse $z^{-1}$ is:The value of $i + i^2 + i^3 + i^4$ is:The product $(2 + 3i)(2 - 3i)$ equals:The modulus $|1 - i|$ equals: