The domain of $f(x)=\sqrt{4-x^2}$ is:
A$[0,2]$
B$(-2,2)$
C$[-2,2]$
D$\mathbb{R}$
Answer & Solution
Correct answer: C. $[-2,2]$
Need 4−x² ≥ 0 ⟹ x² ≤ 4 ⟹ −2 ≤ x ≤ 2, i.e. [−2, 2].
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