The domain of $f(x)=\sqrt{4-x^2}$ is:
A$[0,2]$
B$(-2,2)$
C$[-2,2]$
D$\mathbb{R}$
Answer & Solution
Correct answer: C. $[-2,2]$
Need 4−x² ≥ 0 ⟹ x² ≤ 4 ⟹ −2 ≤ x ≤ 2, i.e. [−2, 2].
Related questions
Domain, co-domain and range were first introduced in:If a function f is invertible, then f must be:Applying f first and then g gives the composition written:Mapping students to roll numbers is one-one because:For f(x) = 2x from R to R, the function is:For f(x) = 2x from N to N, the function is:A function is invertible exactly when it is:A function that is both one-one and onto is called: