Home › JEE Main › mathematics › Relations and Functions › The domain of the function $f(x)=\dfrac{1}{x-2}$…
The domain of the function $f(x)=\dfrac{1}{x-2}$ is:
A$[2,\infty)$
B$\{2\}$
C$\mathbb{R}$
D$\mathbb{R}\setminus\{2\}$
Answer & Solution
Correct answer: D. $\mathbb{R}\setminus\{2\}$
1/(x−2) is undefined at x=2, so the domain is all reals except 2.
Related questions
The graph of $f(x) = 1/x$ in $\mathbb{R} - \{0\}$ is:The function $f: \mathbb{R} \to \mathbb{R}, f(x) = x^2$ is:A relation $R$ from $A$ to $B$ qualifies as a function when:If $|A| = 3$ and $|B| = 4$, the number of elements in $A \times B$ is:The number of bijective functions from a set with $n$ elements onto itself is:On the set $\{1,2,3\}$, the relation $R = \{(1,1),(2,2),(3,3)\}$ is:A function is invertible if and only if it is:If $f(x) = 2x$ and $g(x) = x + 1$, then $(g\circ f)(x)$ equals: