The distance of the point $(2,3,4)$ from the origin is:
A$\sqrt{9}$
B$\sqrt{29}$
C$9$
D$29$
Answer & Solution
Correct answer: B. $\sqrt{29}$
Distance from origin = √(2²+3²+4²) = √(4+9+16) = √29.
Keep practising Unit 8A: Areas Between Curves
Browse all Unit 8A: Areas Between Curves questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
Let $\mathbf{A}=\langle 1,2,3\rangle$, $\mathbf{B}=\langle 2,0,1\rangle$, and $\mathbf{C}=For nonzero vector $\mathbf{A}$, which expression gives a vector in the same direction as When subtracting vectors, $\vec A-\vec B$ is evaluated asThe projection of vector $\vec A$ on vector $\vec B$ is given byWhich statement about a null vector is correct?If $\omega$ is a non-real cube root of unity, find the value of $1 + \omega + \omega^2$.Find the modulus of the complex number $z = 3 + 4i$.The locus of the point $z$ in the Argand plane satisfying $|z - 2| = |z + 2|$ is: