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The cartesian equation of a line through $(x_1,y_1,z_1)$ with direction ratios $a,b,c$ is:
A$\tfrac{x-x_1}{a}+\tfrac{y-y_1}{b}+\tfrac{z-z_1}{c}=1$
B$\tfrac{a}{x-x_1}=\tfrac{b}{y-y_1}=\tfrac{c}{z-z_1}$
C$\tfrac{x-x_1}{a}=\tfrac{y-y_1}{b}=\tfrac{z-z_1}{c}$
D$ax+by+cz=0$
Answer & Solution
Correct answer: C. $\tfrac{x-x_1}{a}=\tfrac{y-y_1}{b}=\tfrac{z-z_1}{c}$
The symmetric (cartesian) form of a line is (x−x₁)/a = (y−y₁)/b = (z−z₁)/c.
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