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The multiplicative inverse of (3 + 4i) is

A(3 − 4i)/25
B(3 − 4i)/7
C(3 + 4i)/25
D3 − 4i
Answer & Solution
Correct answer: A. (3 − 4i)/25
We have 1/(3+4i) = (3−4i)/((3)²+(4)²). So 1/(3+4i) = (3−4i)/25.
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