Uttarakhand Board Class 12 inversetrigonometric — practice questions
16 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice Uttarakhand Board Class 12 inversetrigonometric in the app →The domain of the function $f(x) = in^{-1}(x)$ isThe range of $\cos^{-1}(x)$ isFor every $x \in [-1, 1]$, the value of $ in^{-1}(x) + \cos^{-1}(x)$ isThe principal value of $\tan^{-1}(1)$ is$\tan^{-1}\left(\tfrac{1}{2}\right) + \tan^{-1}\left(\tfrac{1}{3}\right)$ equals$\cot^{-1}\left(-\tfrac{1}{ qrt{3}}\right) = $$ in^{-1}\left( in\tfrac{2\pi}{3}\right)$ equals$\cos^{-1}\left(\cos\tfrac{7\pi}{6}\right)$ equals$\tan^{-1}(1) + \tan^{-1}(2) + \tan^{-1}(3) = $$\displaystyle um_{n=1}^{\infty} \tan^{-1}\left(\frac{1}{n^2 + n + 1}\right)$ equalsFor $x = -2$, the value of $\tan^{-1}\left(\dfrac{2x}{1-x^2}\right)$ equalsAll real $x$ satisfying $ in^{-1}(x) + in^{-1}(1-x) = \cos^{-1}(x)$ areThe principal value of $ in^{-1}(1/2)$ is:For $x \in [-1, 1]$, the identity $ in^{-1}x + \cos^{-1}x$ equals:The value of $\cos^{-1}(-1)$ is:The value of $ in(\tan^{-1}(3/4))$ is: