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The radius of a nucleus of mass number $A$ is approximately $R = R_0 A^{1/3}$ with $R_0 = 1.33 \times 10^{-15}\,m$. The radius of a $^{64}Cu$ nucleus is approximately
A$5.3 \times 10^{-15}\,m$
B$1.33 \times 10^{-15}\,m$
C$2.7 \times 10^{-13}\,m$
D$8.5 \times 10^{-14}\,m$
Answer & Solution
Correct answer: A. $5.3 \times 10^{-15}\,m$
$R = 1.33 \times 10^{-15} \times 64^{1/3} = 1.33 \times 10^{-15} \times 4 = 5.3 \times 10^{-15}\,m$.
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