The radius of a nucleus of mass number $A$ is approximately $R = R_0 A^{1/3}$ with $R_0 = 1.33 \times 10^{-15}\,m$. The radius of a $^{64}Cu$ nucleus is approximately
A$5.3 \times 10^{-15}\,m$
B$1.33 \times 10^{-15}\,m$
C$2.7 \times 10^{-13}\,m$
D$8.5 \times 10^{-14}\,m$
Answer & Solution
Correct answer: A. $5.3 \times 10^{-15}\,m$
$R = 1.33 \times 10^{-15} \times 64^{1/3} = 1.33 \times 10^{-15} \times 4 = 5.3 \times 10^{-15}\,m$.
Related questions
Calcium-40 (Z=20, A=40) and Argon-40 (Z=18, A=40) are best described as:Atoms of the SAME element with DIFFERENT mass numbers are called:An atom of chlorine has atomic number Z = 17 and mass number A = 37. The number of neutronThe atomic number (Z) of an element is equal to the:The neutron was discovered by:Bohr's model of the atom fixed Rutherford's instability problem by proposing that electronRutherford's gold foil experiment concluded that most of the atom is:The Rydberg constant for hydrogen, in SI units, is