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Re-derive the incompressibility condition: starting from $\partial\rho/\partial t + \nabla\cdot(\rho\mathbf{u}) = 0$ with ρ = const, what remains?

A{'text': '$\\rho = \\nabla\\cdot\\mathbf{u}$', 'label': 'A'}
B{'text': '$\\nabla\\cdot\\mathbf{u} = 0$', 'label': 'B'}
C{'text': '$\\partial\\rho/\\partial t = 0$ only', 'label': 'C'}
D{'text': '$\\rho\\mathbf{u} = 0$', 'label': 'D'}
Answer & Solution
Correct answer: B. {'text': '$\\nabla\\cdot\\mathbf{u} = 0$', 'label': 'B'}
With ρ = const: ∂ρ/∂t = 0 and ρ factors out of divergence. We get ρ∇·u = 0, so ∇·u = 0. Incompressible flow has zero velocity divergence.
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