Home › SSC CGL › Quantitative Aptitude › Percentages › **Percentages — formulas used here.** - Definiti…
**Percentages — formulas used here.** - Definition. $x\%$ means $\tfrac{x}{100}$. - Increase consumption. If price rises by $R\%$ and spending must stay constant, consumption falls by $\tfrac{R}{100+R} \times 100\%$. - Decrease consumption. If price falls by $R\%$ and spending must stay constant, consumption rises by $\tfrac{R}{100-R} \times 100\%$. - Growth. A population $P$ growing at $R\%$ a year becomes $P(1 + \tfrac{R}{100})^n$ after $n$ years, and was $P / (1 + \tfrac{R}{100})^n$, $n$ years ago. - Depreciation. A value $V$ depreciating at $R\%$ a year becomes $V(1 - \tfrac{R}{100})^n$ after $n$ years. - Reciprocal comparisons. If A is $R\%$ more than B, then B is $\tfrac{R}{100+R} \times 100\%$ less than A. If A is $R\%$ less than B, then B is $\tfrac{R}{100-R} \times 100\%$ more than A. **Question.** A merchant marks his goods up by $40\%$ over cost price and then offers a discount of $25\%$ on the marked price. What is his net profit (or loss) percentage?
ALoss of $5\%$
BNo profit, no loss
CProfit of $5\%$
DProfit of $15\%$
Answer & Solution
Correct answer: C. Profit of $5\%$
**Set up.** Let CP $= 100$. Marked price $= 100 \times 1.40 = 140$. Selling price after $25\%$ discount $= 140 \times (1 - 0.25) = 140 \times 0.75 = 105$.
**Profit calculation.** Profit $= 105 - 100 = 5$, on a base of $100$, so $5\%$ profit.
**Why option D is wrong.** A common mistake is to subtract the percentages directly ($40 - 25 = 15$). The error is that the $25\%$ discount is on the *marked* price, not the cost price — the bases are different, so the percentages don't add.
**Why option B is wrong.** Another tempting trap is to assume markup and discount cancel — but they only cancel exactly when discount = mark-up / (1 + mark-up), i.e. about $28.6\%$ for a $40\%$ markup.
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