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Which relation shown with the loop diagram is the Kirchhoff's Voltage Law equation for that circuit? 
A$V_1+V_2+V_3+V_4+V_5+V_6+V_7-V_s=0$
B$V_1+V_2+V_3=V_4+V_5+V_6+V_7$
C$V_s+V_1+V_2+V_3+V_4+V_5+V_6+V_7=0$
D$V_s=0$
Answer & Solution
Correct answer: A. $V_1+V_2+V_3+V_4+V_5+V_6+V_7-V_s=0$
In the loop figure, the source provides a voltage rise, while the labeled elements represent voltage drops according to the shown polarities. Therefore the algebraic loop equation is $V_1+V_2+V_3+V_4+V_5+V_6+V_7-V_s=0$.
