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In the junction figure, suppose $I_1$, $I_2$, and $I_3$ each equal $1\,\text{A}$, and $I_4$ and $I_5$ are $0.5\,\text{A}$ each. What is $I_6$? ![](https://qallery.app/diagrams/v2_653a95f0d181/img-000.jpeg)

A$1\,\text{A}$
B$2\,\text{A}$
C$3\,\text{A}$
D$4\,\text{A}$
Answer & Solution
Correct answer: B. $2\,\text{A}$
Using the figure's directions, $I_1+I_2+I_3=I_4+I_5+I_6$. So $1+1+1=0.5+0.5+I_6$, which gives $3=1+I_6$ and hence $I_6=2\,\text{A}$. ![](https://qallery.app/diagrams/v2_653a95f0d181/img-000.jpeg)
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