∫ from 0 to π sin²x dx =
Aπ/2 (use sin²x = (1 - cos 2x)/2)
B2
Cπ/4
Dπ
Answer & Solution
Correct answer: A. π/2 (use sin²x = (1 - cos 2x)/2)
sin²x = (1 - cos 2x)/2. ∫₀^π sin²x dx = (1/2) ∫₀^π (1 - cos 2x) dx = (1/2)[π - 0] = π/2.
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