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∫ 1/(1 + x²) dx =

Ax²/2
Bln(1 + x²)
Carctan x + C
Dtan x
Answer & Solution
Correct answer: C. arctan x + C
∫ dx/(1 + x²) = arctan x + C (= tan⁻¹ x + C). Standard result. Used in trig substitution x = tan θ.
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