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∫ ln x dx (by parts: u = ln x, dv = dx):

Aln x / x
Bx ln x - x + C
Cx ln x
Dln²x
Answer & Solution
Correct answer: B. x ln x - x + C
u = ln x, du = dx/x; dv = dx, v = x. We have ∫ ln x dx = x ln x - ∫ x × (1/x). So dx = x ln x - x + C.
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