allery∫ e^x dx =
Ae^x + C
Bx e^x
Cln x
Dx²
Answer & Solution
Correct answer: A. e^x + C
∫ e^x dx = e^x + C. (Exponential is its own integral up to constant.) Similarly ∫ e^(kx) dx = e^(kx)/k + C.
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