alleryIndefinite integral of xⁿ (n ≠ -1):
Axⁿ⁺¹/(n+1) + C
Bxⁿ⁻¹/n
Cn xⁿ⁻¹
Dxⁿ
Answer & Solution
Correct answer: A. xⁿ⁺¹/(n+1) + C
∫ xⁿ dx = xⁿ⁺¹/(n+1) + C (n ≠ -1).
Reverse of power rule for differentiation.
For n = -1: ∫ x⁻¹ dx = ln|x| + C.
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