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Suppose at a node the incoming currents are $4\,\text{A}$ and $6\,\text{A}$, while one outgoing current is $3\,\text{A}$. What must the other outgoing current be?
A$1\,\text{A}$
B$3\,\text{A}$
C$7\,\text{A}$
D$10\,\text{A}$
Answer & Solution
Correct answer: C. $7\,\text{A}$
By KCL, total incoming current equals total outgoing current. So $4+6=3+I$, which gives $I=7\,\text{A}$.