If A is invertible n × n matrix and B is any n × n matrix, then det(A⁻¹BA):
A= det A
B= det A⁻¹
C= det B
DCannot determine
Answer & Solution
Correct answer: C. = det B
det(A⁻¹BA) = det(A⁻¹)·det(B)·det(A) = (1/det A)·det B·det A = det B. Similar matrices have the same determinant.
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