alleryThe inverse of a 2x2 matrix [[a,b],[c,d]] is (when det ≠ 0):
A[[d,-b],[-c,a]]
B[[d,-b],[-c,a]] / det
C[[a,-b],[-c,d]]
D[[1/a,1/b],[1/c,1/d]]
Answer & Solution
Correct answer: B. [[d,-b],[-c,a]] / det
A⁻¹ = (1/det A) × [[d,-b],[-c,a]] for 2×2 matrix.
Swap diagonals, negate off-diagonals, divide by determinant.
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