The distance between two cities A and B is 80 km. A motorcycle rider starts from A towards B at 7 am at a speed of 10 km/hr. Another motorcyclist starts from B towards A at 8 am at a speed of 25 km/hr. At what time will they cross each other?
A9 am
B10 am
C10:30 am
D11 am
Answer & Solution
Correct answer: B. 10 am
By 8 am, the first rider has already covered $10$ km, so the remaining distance between them is $80-10=70$ km. Since they move towards each other, relative speed is $10+25=35$ km/hr. Time after 8 am to meet is $70/35=2$ hr. Therefore they meet at 10 am.
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