∫ dx/√(x² + a²) equals:
Aarctan(x/a) + C
Bln |x + √(x²+a²)| + C
Carcsin(x/a) + C
Dx/√(x²+a²) + C
Answer & Solution
Correct answer: B. ln |x + √(x²+a²)| + C
Standard result via x = a tanθ substitution: ∫ dx/√(x² + a²) = ln |x + √(x²+a²)| + C = sinh⁻¹(x/a) + C.
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