∫₀¹ x e^(x²) dx equals:
A(e-1)/2
Be/2
Ce
De²
Answer & Solution
Correct answer: A. (e-1)/2
Let u = x², du = 2x dx. Integral becomes (1/2) ∫₀¹ e^u du = (1/2)[e^u]₀¹ = (1/2)(e - 1).
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