∫ dx/√(1 - x²) equals:
A√(1-x²) + C
B-arcsin x + C
Carctan x + C
Darcsin x + C
Answer & Solution
Correct answer: D. arcsin x + C
This is the standard form for arcsine: ∫ dx/√(1-x²) = arcsin x + C (or sin⁻¹ x). Also ∫ -dx/√(1-x²) = arccos x + C.
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