Which statement correctly distinguishes $\sqrt{16}$ from $\pm\sqrt{16}$?
ABoth represent only the positive square root
B$\sqrt{16}=\pm4$, but $\pm\sqrt{16}=4$
C$\sqrt{16}=4$, but $\pm\sqrt{16}=\pm4$
DBoth represent two square roots, so they are identical in meaning
Answer & Solution
Correct answer: C. $\sqrt{16}=4$, but $\pm\sqrt{16}=\pm4$
The radical symbol $\sqrt{\phantom{x}}$ denotes the positive square root. Hence $\sqrt{16}=4$. If both square roots are required, we write $\pm\sqrt{16}=\pm4$.
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