For the equation $$a\,\mathrm{KMnO_4}+b\,\mathrm{HCl}\rightarrow c\,\m…

Question

For the equation 
$$a\,\mathrm{KMnO_4}+b\,\mathrm{HCl}\rightarrow c\,\mathrm{KCl}+d\,\mathrm{MnCl_2}+e\,\mathrm{H_2O}+f\,\mathrm{Cl_2},$$
if $a=2$, what is the value of $e$ after balancing oxygen atoms?

Accepted Answer

B. 8

Oxygen balancing gives $4a=e$ because each $\mathrm{KMnO_4}$ has 4 oxygen atoms and each $\mathrm{H_2O}$ has 1 oxygen atom. With $a=2$, we get $e=4	imes 2=8$.

Answer

4

Answer

10

Answer

16

For the equation $$a\,\mathrm{KMnO_4}+b\,\mathrm{HCl}\rightarrow c\,\mathrm{KCl}+d\,\mathrm{MnCl_2}+e\,\mathrm{H_2O}+f\,\mathrm{Cl_2},$$ if $a=2$, what is the value of $e$ after balancing oxygen atoms?