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In the right triangle shown, $AB=5\text{ cm}$ and $\angle ACB=30^\circ$. What is the length of $AC$? 
A$5\text{ cm}$
B$5\sqrt{3}\text{ cm}$
C$10\text{ cm}$
D$15\text{ cm}$
Answer & Solution
Correct answer: C. $10\text{ cm}$
Here $AB$ is opposite to angle $C=30^\circ$ and $AC$ is the hypotenuse. Using $\sin 30^\circ=\frac{AB}{AC}$, we get $\frac{1}{2}=\frac{5}{AC}$. Therefore $AC=10\text{ cm}$.
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