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The points of trisection of the line segment joining $A(2,-2)$ and $B(-7,4)$ are 
A$(-1,0)$ and $(-4,2)$
B$(-4,0)$ and $(-1,2)$
C$(1,0)$ and $(-4,2)$
D$(-1,2)$ and $(-4,0)$
Answer & Solution
Correct answer: A. $(-1,0)$ and $(-4,2)$
The trisection points divide the segment in ratios $1:2$ and $2:1$. Using the section formula, the first point is $\left(\dfrac{1(-7)+2(2)}{3},\dfrac{1(4)+2(-2)}{3}\right)=(-1,0)$ and the second is $\left(\dfrac{2(-7)+1(2)}{3},\dfrac{2(4)+1(-2)}{3}\right)=(-4,2)$.
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