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A 3.00-V flashlight bulb has a hot resistance of 3.60 ohms. What current flows through it?
A0.83 A
B1.20 A
C10.8 A
D0.12 A
Answer & Solution
Correct answer: A. 0.83 A
1. Ohm's law gives current as I = V/R.
2. Substitute: I = 3.00 V / 3.60 ohms.
3. Divide: I = 0.83 A.
4. 10.8 A is the trap of multiplying voltage by resistance instead of dividing.
_Source: OpenStax College Physics (CC BY 4.0), Ch 20 "Electric Current, Resistance, and Ohm's Law", section 20.2 Ohm's Law: Resistance and Simple Circuits_
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