Angie swims the 50 meter freestyle in 26.2 seconds against a team mean of 27.2 and standard deviation 0.8. Beth swims 27.3 seconds against a team mean of 30.1 and standard deviation 1.4. For times, lower is better. Who is faster relative to her own team?

1. Comparing values from different data sets requires z-scores, not raw values. 2. A z-score counts standard deviations from the mean: z = (value - mean)/standard deviation. 3. Angie: z = (26.2 - 27.2)/0.8 = -1.0/0.8 = -1.25. 4. Beth: z = (27.3 - 30.1)/1.4 = -2.8/1.4 = -2.0. 5. For race times, a more negative z-score means further below the team's average time, which is better. 6. Beth is 2.0 standard deviations faster than her team while Angie is only 1.25, so Beth wins the comparison. 7. Option B judges by raw seconds, exactly the mistake z-scores exist to fix when teams differ. 8. Option A stops after computing Angie's z-score without comparing it to Beth's, and option C ignores the arithmetic. _Source: OpenStax Introductory Business Statistics (CC BY 4.0), Ch 2 "Descriptive Statistics", section 2.7 Measures of the Spread of the Data_