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HomeSTAAR EOC Algebra IMathematicsFactoring › Using trial and error, factor: 14x^2 - 47x - 7.

Using trial and error, factor: 14x^2 - 47x - 7.

A(2x+7)(7x-1)
B(2x-7)(7x+1)
C(x-7)(14x+1)
D(x+1)(14x-7)
Answer & Solution
Correct answer: B. (2x-7)(7x+1)
1. The factors of 14x squared are x and 14x, or 2x and 7x. 2. The last term is -7, which is negative, so its factors must have opposite signs: 1 and -7, or -1 and 7. 3. Testing the combination (2x - 7)(7x + 1), the outer and inner terms are 2x and -49x, which combine to -47x, matching the middle term. 4. Check by multiplying: 14x squared + 2x - 49x - 7 gives back 14x squared - 47x - 7. _Source: OpenStax Elementary Algebra (CC BY 4.0), Ch 7 "Factoring", section 7.3 Factor Quadratic Trinomials with Leading Coefficient Other than 1_
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