Factor by grouping: x^2 + 3x - 2x - 6.
A(x-3)(x+2)
B(x+6)(x-1)
C(x+3)(x-2)
D(x-6)(x+1)
Answer & Solution
Correct answer: C. (x+3)(x-2)
1. Separate the four terms into two parts: (x squared + 3x) and (-2x - 6).
2. Factor x from the first part to get x(x + 3), and factor -2 from the second part to get -2(x + 3).
3. Be careful with the signs when factoring the GCF from the last two terms, since -2 must be pulled out, not 2.
4. Both parts share the factor (x + 3), so the expression factors to (x + 3)(x - 2).
_Source: OpenStax Elementary Algebra (CC BY 4.0), Ch 7 "Factoring", section 7.1 Greatest Common Factor and Factor by Grouping_
Related questions
Factor: x^3 + 64.According to the Sum and Difference of Cubes Pattern, how does a^3+b^3 factor?Factor completely: 36x^2y - 48xy + 16y.Factor completely: 8x^2y - 98y.Factor completely: 6x^2 + 96.What happens when you try to factor a sum of squares like a^2 + b^2?What is the completely factored form of x^4 - y^4?Factor: 100 - h^2.