Three resistors of 10 ohm, 25 ohm, and 15 ohm are connected in parallel across a 3 V battery. Which resistor carries the largest branch current?

1. Each resistor in this parallel combination sees the same 3 V, since both ends of each resistor connect to the same two wires. 2. Ohm's law gives the branch current as I = V/R, with V fixed at 3 V for all three branches. 3. With V fixed, a smaller R in the denominator produces a larger current I. 4. I_10 = 3 V / 10 ohm = 0.30 A, I_25 = 3 V / 25 ohm = 0.12 A, I_15 = 3 V / 15 ohm = 0.20 A. 5. Comparing these three values, 0.30 A is the largest, corresponding to the 10 ohm resistor. 6. This is a trap worth naming directly: the smallest resistor carries the most current, and the largest resistor carries the least, the opposite of what a series circuit would suggest. 7. The option claiming all three carry the same current describes series resistors, not parallel ones, and is ruled out by the differing values computed above. _Source: OpenStax Physics (CC BY 4.0), Ch 19 "Electrical Circuits", section Find the Current through Parallel Resistors_