In a single loop with a battery and resistors connected one after the other, why does the current stay the same at every point around the loop?

1. Suppose, for contradiction, that current were not the same everywhere along the loop. 2. Mobile charge would then bunch up at some point, since more charge would arrive there than leaves. 3. Extra bunched charge raises the local voltage at that point. 4. Current in a resistive path flows from higher voltage toward lower voltage, so the raised local voltage pushes current away from the bunch in both directions. 5. Pushing current away from the bunch drains the excess charge back out, restoring the original balance rather than letting it grow. 6. This is a self-correcting, negative-feedback mechanism, not a runaway one. 7. The option describing the bunch lowering voltage misidentifies which way extra charge changes local voltage. 8. The option describing the higher voltage pushing current further into the bunch would make any small imbalance grow without limit, which contradicts the observed steady, constant current. 9. So the only self-consistent explanation is that a voltage rise from bunching pushes current away, which decreases the voltage back down and keeps the current uniform. _Source: OpenStax Physics (CC BY 4.0), Ch 19 "Electrical Circuits", section 19.2 Series Circuits_