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Two 80 ohm resistors are connected one after the other, and a current of 0.15 A flows through them. What is the total voltage drop across the two resistors?
A12 V
B24 V
C6.0 V
D48 V
Answer & Solution
Correct answer: B. 24 V
1. For resistors connected one after the other, the equivalent resistance adds: R_equiv = 80 ohm + 80 ohm = 160 ohm.
2. Apply Ohm's law to the combination: V = I x R_equiv.
3. V = (0.15 A)(160 ohm) = 24 V.
4. 12 V would result from using only a single 80 ohm resistor instead of both.
_Source: OpenStax Physics (CC BY 4.0), Ch 19 "Electrical Circuits", section 19.2 Series Circuits_
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