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How long would it take a steady 10 mA current to deliver 5.0 mC of charge to a capacitor?
A5.0 sec
B0.50 sec
C0.050 sec
D50 sec
Answer & Solution
Correct answer: B. 0.50 sec
1. Current is charge over time, I = deltaQ / deltat, so deltat = deltaQ / I.
2. Substitute deltaQ = 5.0 x 10^-3 C and I = 10 x 10^-3 A.
3. deltat = (5.0 x 10^-3 C) / (10 x 10^-3 A) = 0.50 s.
_Source: OpenStax Physics (CC BY 4.0), Ch 19 "Electrical Circuits", section Direct and Alternating Current_
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