alleryStart learning →Deuterium has a binding energy of 3.56 x 10^-13 J. Using c = 3.00 x 10^8 m/s, what is its mass defect?
A3.96 x 10^-30 kg
B3.20 x 10^-4 kg
C1.19 x 10^-21 kg
D1.07 x 10^-4 kg
Answer & Solution
Correct answer: A. 3.96 x 10^-30 kg
1. Rearranging E0 = m c^2 for mass gives m = E0 divided by c^2.
2. Substitute E0 = 3.56 x 10^-13 J and c^2 = 9.00 x 10^16.
3. Dividing gives m = 3.96 x 10^-30 kg.
4. 3.20 x 10^-4 kg and 1.07 x 10^-4 kg would result from dividing by c instead of c squared.
5. 1.19 x 10^-21 kg does not match this division at all.
6. So 3.96 x 10^-30 kg is correct.
_Source: OpenStax Physics (CC BY 4.0), Ch 10 "Special Relativity", section 10.2 Consequences of Special Relativity_
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