A bullet is accelerated from the firing chamber to the end of the barrel at an average rate of 6.30 x 10^5 m/s^2 for 8.10 x 10^-4 s, starting from rest. What is its muzzle velocity?
A7.79 m/s
B51.0 m/s
C510 m/s
D1020 m/s
Answer & Solution
Correct answer: C. 510 m/s
1. Starting from rest, use v = v_0 + at with v_0 = 0.
2. v = (6.30 x 10^5 m/s^2)(8.10 x 10^-4 s).
3. v = 510 m/s.
_Source: OpenStax Physics (CC BY 4.0), Ch 3 "Acceleration", section 3.2 Representing Acceleration with Equations and Graphs_
Related questions
When air resistance is not a factor, all objects near Earth's surface in free fall accelerWhat is the SI unit of acceleration?The same subway train later slows from 30.0 km/h (8.333 m/s) to a complete stop in 8.00 s.A subway train accelerates from rest to 30.0 km/h (8.33 m/s) in 20.0 s. What is its averagA car's speed decreases as the driver brakes. Everyday language calls this "deceleration."Pushing the gas pedal of a car increases its velocity. In physics terms, this change in veDrag racers compete over a standing start on a track of what length?During launch and reentry, about how many g's does the space shuttle produce for its occup