A swan on a lake must reach 6.00 m/s to take off. Starting from rest, it accelerates at a constant 0.350 m/s^2. How far does it travel before becoming airborne?
A8.60 m
B17.1 m
C34.3 m
D51.4 m
Answer & Solution
Correct answer: D. 51.4 m
1. Starting from rest, use v^2 = 2ad, so d = v^2 / (2a).
2. d = (6.00 m/s)^2 / (2 x 0.350 m/s^2) = 36.0 / 0.700.
3. d = 51.4 m.
_Source: OpenStax Physics (CC BY 4.0), Ch 3 "Acceleration", section 3.2 Representing Acceleration with Equations and Graphs_
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