The driver of a sports car travelling at 10.0 m/s presses the accelerator for 5.0 s, raising the speed to 30.0 m/s. What was the average acceleration during that interval?
A-4.0 m/s^2
B2.0 m/s^2
C4.0 m/s^2
D6.0 m/s^2
Answer & Solution
Correct answer: C. 4.0 m/s^2
1. delta v = 30.0 m/s - 10.0 m/s = 20.0 m/s.
2. a = delta v / delta t = 20.0 m/s / 5.0 s.
3. a = 4.0 m/s^2.
_Source: OpenStax Physics (CC BY 4.0), Ch 3 "Acceleration", section 3.1 Acceleration_
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