An Olympic-class sprinter starts a race with a constant acceleration of 4.50 m/s^2. What is her speed 2.40 s later?
A1.88 m/s
B4.50 m/s
C10.8 m/s
D44.1 m/s
Answer & Solution
Correct answer: C. 10.8 m/s
1. Starting from rest, use v = v_0 + at with v_0 = 0.
2. v = (4.50 m/s^2)(2.40 s).
3. v = 10.8 m/s.
_Source: OpenStax Physics (CC BY 4.0), Ch 3 "Acceleration", section 3.2 Representing Acceleration with Equations and Graphs_
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