In a potato race, a bucket is placed at the starting point, which is $5\text{ m}$ from the first potato, and the other potatoes are placed $3\text{ m}$ apart in a straight line. There are ten potatoes in the line as shown. What total distance does the competitor run to bring all potatoes back to the bucket? 

The potato distances from the bucket are $5,8,11,\ldots$ for 10 potatoes, so they form an AP with $a=5$, $d=3$, $n=10$. Since the competitor runs to each potato and back, total distance is twice the sum of these distances. 1. Sum of distances to the potatoes: $$S_{10}=\frac{10}{2}[2\cdot 5+(10-1)\cdot 3]=5(10+27)=185.$$ 2. Total running distance: $$2\times 185=370\text{ m}.$$ Option B is tempting if one incorrectly counts only one-way distances for some trips. Option D can arise from using 11 potatoes by mistake. Option A comes from a wrong AP sum. So the correct total is $370\text{ m}$.